# Line slope calculator x-8y=-8

**Straight line given by points A[0; 1] and B[8; 2]**

## Calculation:

**Slope-intercept form of line:**y = 0.125x+1

**Canonical form of the line equation:**x-8y+8 = 0

**Parametric form of the line equation:**

x = 8t

y = t+1 ; t ∈ R

**Slope:**m = 0.125

**Slope angle of line: φ =**7°7'30″ = 0.1244 rad

**X intercept:**x

_{0}= -8

**Y intercept:**y

_{0}= q = 1

**Distance line from the origin:**d

_{0}= 0.9923

**The length of the segment AB: |AB| =**8.0623

**Vector: AB =**(8; 1)

**Normal vector: n =**(1; -8)

**Midpoint of the segment AB: M =**[4; 1.5]

**Perpendicular Bisector equation:**8x+y-33.5 = 0

**Vector OA = (0; 1) ; |OA| = 1**

**Vector OB = (8; 2) ; |OB| = 8.2462**

**Scalar product OA .OB = 2**

**Angle ∠ AOB = 75°57'50″ = 1.3258 rad**